А Решите уравнение.
Б Найдите корни этого
уравнения, принадлежащие указанному промежутку.
{log(5,cos(x)-sin(2*x)+25)=2 ,2*Pi<=x,x<=7*Pi/2}
{log(2,cos(x)+sin(2*x)+8)=3 ,3*Pi/2<=x,x<=3*Pi}
{log(3,sin(x)-sin(2*x)+27)=3 ,-7*Pi/2<=x,x<=-2*Pi}
{2*sin(x)^3 = cos(x-(1/2)*Pi) ,-3*Pi/2<=x,x<=-Pi/2}
{2*sin(x)^3+cos(x+(1/2)*Pi) = 0 ,-3*Pi/2<=x,x<=-Pi/2}
{4*sin(x)^3 = cos(x-5*Pi*(1/2)) ,3*Pi/2<=x,x<=5*Pi/2}
{4*sin(x)^3-3*cos(x-Pi/2) = 0,7Pi/2<=x,x<=9Pi/2}
{4 sin(x)^3+ 3 cos(x+ Pi/2)=0,7Pi/2<=x,x<=9Pi/2}
{4*sin(x)^3-cos(x-Pi/2) = 0,3Pi/2<=x,x<=5Pi/2}
{2*cos(x)^3 = sin(5*Pi/2-x),3Pi/2<=x,x<=5Pi/2}
{2*cos(x)^3-sin(9*Pi/2-x) = 0,-2Pi<=x,x<=-Pi}
{4*cos(x)^3+3*sin(x-Pi/2) = 0,-2Pi<=x,x<=-Pi}
{4*cos(x)^3+sin(x-Pi/2) = 0,Pi<=x,x<=2Pi}
{4*cos(x)^3 = 3*sin(x+Pi/2),-2Pi<=x,x<=-Pi}
{4*cos(x)^3-sin(x+Pi/2) = 0,Pi<=x,x<=2Pi}
{6*sin(x)^2+7*cos(x)-1 = 0,-7Pi/2<=x,x<=-5Pi/2}
{6*sin(x)^2+5*cos(x)-2 = 0,5Pi/2<=x,x<=4Pi}
{4*cos(x)^2-8*sin(x)+1 = 0,-3Pi<=x,x<=-3Pi/2}
{cos(2*x)+sin(x)^2 = 1/4,3Pi<=x,x<=9Pi/2}
{cos(2*x)+sin(2*x) = 1,3Pi<=x,x<=9Pi/2}
{cos(2*x)+1/4 = cos(x)^2,2Pi<=x,x<=7Pi/2}
{cos(2*x)+1/2 = cos(x)^2,-2Pi<=x,x<=-Pi/2}
{cos(2*x)+3/4 = cos(Pi-x)^2,-4Pi<=x,x<=-5Pi/2}
{cos(2*x)+sin(x)^2 = 1/2,-7Pi/2<=x,x<=-2Pi}
{cos(2*x) = 3/4-sin(x)^2,2Pi<=x,x<=7Pi/2}
{cos(2*x)+3/4-cos(x)^2 = 0,3Pi<=x,x<=9Pi/2}
{cos(2*x)-sin(x)^2 = 1/4,3Pi<=x,x<=9Pi/2}
{cos(2*x)+3/4 = cos(x)^2,-4Pi<=x,x<=-5Pi/2}
{cos(2*x)+sin(x)^2 = 1/4,3Pi<=x,x<=9Pi/2}
{sin(2*x) = sin(x+3*Pi/2),7Pi/2<=x,x<=9Pi/2}
{cos(5*Pi/2-2*x)-sin(x) = 0,-3Pi/2<=x,x<=-Pi/2}
{cos(Pi/2+2*x)+sin(x) = 0,3Pi/2<=x,x<=5Pi/2}
{cos((1/2)*Pi-2*x)+sin(x) = 0,-3Pi/2<=x,x<=-Pi/2}
{sin(2*x) = sin(x+3*Pi*(1/2)),-7Pi/2<=x,x<=-5Pi/2}
{sin(2*x) = cos(x-3*Pi/2),5Pi/2<=x,x<=7Pi/2}
{sin(2*x) = cos(5*Pi*(1/2)-x),-7Pi/2<=x,x<=-5Pi/2}
{36^sin(2*x) = 6^(2*sin(x)),-7Pi/2<=x,x<=-5Pi/2}
{49^sin(2*x) = 7^(2*cos(Pi/2-x)),-7Pi/2<=x,x<=-5Pi/2}
{sin(2*x)+sqrt(3)*sin(x) = 0,5Pi/2<=x,x<=7Pi/2}
{6*sin(x)^2+5*sin((1/2)*Pi-x)-2 = 0,-5Pi<=x,x<=-7Pi/2}
{2*cos(2*x)-8*sin(x)+3 = 0,3Pi/2<=x,x<=3Pi}
{4*cos(x)^2+4*cos(x+(1/2)*Pi)-1 = 0,Pi<=x,x<=5Pi/2}
{sqrt(2)*sin(x)^3-sqrt(2)*sin(x)+cos(x)^2 = 0,-5Pi/2<=x,x<=-Pi}
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